Answer:
Given expression: 6(2b-4). To find the value of 6(2b-4) at b= 5, we need to substitute the b=5 in the expression, we get….Therefore, the value of 6(2b-4) is 36, when b=5.
Explanation:
Given expression: 6(2b-4). To find the value of 6(2b-4) at b= 5, we need to substitute the b=5 in the expression, we get….Therefore, the value of 6(2b-4) is 36, when b=5.
Above it says the molecular weights are
NH3- 17g/mol and SF6-146 g/mol
Well 1 mole of SF6 is 146.048 grams (i added hte atomic masses of each element). So then the number of moles in 0.85 grams would be 0.00582000438 moles.
<span><span><span>= 1mole / </span><span>146.048g *</span></span> 0.85g</span>
so we would need 0.00582000438 moles of NH3 to have the same number of molecules.
One mole of NH3 is 17.030519999989988 grams (i added each atoms mass). so 0.00582000438 moles of NH3 would be:
<span><span><span>= 17.030519999989988 g / </span><span>mole * </span></span>0.00582000438moles</span>
that equals 0.09911770099 grams.
so 0.09911770099 grams is the answer if you round that you get about 0.1 grams
Answer:
pH= 0.92
Explanation:
HNO3-> H^+ +NO3^-
HNO3 is a strong acid, so it fully dissociates
[HNO3] = 0.12M [H^+] = 0.12M
pH= -log[H^+]
pH=-log[.12] = 0.92
pH = 0.92
Answer:
will form a precipitate of insoluble when aqueous is added.
Explanation:
According to solubility rule-
all carbonates are insoluble except group IA compounds and
all salts of sodium are soluble
When is added to given solutions, a double displacement reaction takes place in each solution to form a sodium salt and a carbonate salt.
So, in accordance with solubility rule, addition of into will result precipitation of insoluble
Reaction:
Answer:
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