a)
A: Copper
B: CuO
C:
D: $\mathrm{CuCO_3}$
E: $\mathrm{CO_2}$
F: $\mathrm{Cu(NO_3)_2}$
b)
$\mathrm{CuO+ H_2SO_4}\rightarrow \mathrm{CuSO_4 + H_2O}$
c)
$\mathrm{CuCO_3+ 2HNO_3}\rightarrow \mathrm{Cu(NO_3)_2+ CO_2+ H_2O}$
Answer:
for the given reaction is -99.4 J/K
Explanation:
Balanced reaction:
where represents standard entropy.
Plug in all the standard entropy values from available literature in the above equation:
So, for the given reaction is -99.4 J/K
Explanation:
Because a large amount of energy is required to break the strong inter-ionic attraction.
CaS => Ca2+ & S2-
Sulfur reacts with oxygen to produce sulfur dioxide. That is for every mole of sulfur reacted, one mole of sulfur dioxide also is produced. With the given mole of sulfur dioxide, the amount of sulfur in mass is determined by multiplying the number of moles to the molar mass of sulfur (32 g/mol).