The uniforms will cost 1,360, so yes they have enough money to buy 11 uniforms.
Hope this helps.
Answer:
The correct answer is 15 cm.
Step-by-step explanation:
Let the width of the required poster be a cm.
We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.
Similarly total margin combining both the sides is (4+4=) 8 cm.
So the required printing area of the poster is given by {( a-10 ) × ( a - 8) }
This area is equal to 125 as per as the given problem.
∴ (a - 10) × (a - 8) = 125
⇒ - 18 a +80 -125 =0
⇒ - 18 a -45 = 0
⇒ (a-15) (a-3) = 0
By law of trichotomy the possible values of a are 15 and 3.
But a=3 is absurd as a 4.
Thus the required answer is 15 cm.
4x+60+ x+15=180
5x+75=180
5x=105
x=21
Two linear angles are supplementary thereom
Answer:
16
Step-by-step explanation:
Let x be the original radius. Given that a semicircle will have an arc length of half of a circumference and C=2pr, the arc length will be just pr.
Now the difference of arc is then going to be:
p(6+x)-px
p(6+x-x)
6p inches
So the arc will be 6p inches longer. Or if you wish to approximate...
≈18.85 inches