Answer:
Explanation:
Given data
Distance S=6.10 m
Initial Speed u=12.0 m/s
To find
Final Speed v
Solution
From third equation of motion we know that:
where
v is final velocity
u is initial velocity
a is acceleration
S is distance
Substitute the given values to find v
<em>Kinetic Energy</em>
=><em><u>It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.</u></em>
<em>Potential</em><em> </em><em>Energy</em><em> </em>
<u><em>=</em><em>></em><em>potential energy is the energy held by </em></u><em><u>an</u></em>
<em><u> object because of its position relative to </u></em><em><u>other</u></em>
<em><u> objects, stresses within itself, its </u></em><em><u>electric</u></em>
<em><u> charge, or other factors.</u></em>
<h2>Difference:</h2>
=>Potential energy is a <u>stored</u> energy on the other hand kinetic energy is the energy of an object or a system's particle in <em><u>Motion</u></em>.
Answer: Reliable and trusted
Answer:
x = 41.28 m
Explanation:
This is a projectile launching exercise, let's find the time it takes to get to the base of the cliff.
Let's start by using trigonometry to find the initial velocity
cos 25 = v₀ₓ / v₀
sin 25 = Iv_{oy} / v₀
v₀ₓ = v₀ cos 25
v_{oy} = v₀ sin 25
v₀ₓ = 22 cos 25 = 19.94 m / s
v_{oy} = 22 sin 25 = 0.0192 m / s
let's use movement on the vertical axis
y = y₀ + v_{oy} t - ½ g t²
when reaching the base of the cliff y = 0 and the initial height is y₀ = 21 m
0 = 21 + 0.0192 t - ½ 9.81 t²
4.905 t² - 0.0192 t - 21 = 0
t² - 0.003914 t - 4.2813 =0
we solve the quadratic equation
t =
t =
t₁ = 2.07 s
t₂ = -2.067 s
since time must be a positive scalar quantity, the correct result is
t = 2.07 s
now we can look up the distance traveled
x = v₀ₓ t
x = 19.94 2.07
x = 41.28 m
Answer:
The horse father from the center has a greater tangential speed. Although both horses complete one circle in the same time period, the one farther from the center covers a greater distance during that same period.
Explanation: