160 test=100%
Therefore:
160 test------------------100%
104 test------------------ x
x=(104 test*100%) / 160 test=65%
Answer: 104 test is the 65% of 160 test
First we need to find k ( rate of growth)
The formula is
A=p e^kt
A future bacteria 4800
P current bacteria 4000
E constant
K rate of growth?
T time 5 hours
Plug in the formula
4800=4000 e^5k
Solve for k
4800/4000=e^5k
Take the log for both sides
Log (4800/4000)=5k×log (e)
5k=log (4800/4000)÷log (e)
K=(log(4,800÷4,000)÷log(e))÷5
k=0.03646
Now use the formula again to find how bacteria will be present after 15 Hours
A=p e^kt
A ?
P 4000
K 0.03646
E constant
T 15 hours
Plug in the formula
A=4,000×e^(0.03646×15)
A=6,911.55 round your answer to get 6912 bacteria will be present after 15 Hours
Hope it helps!
Answer:
Step-by-step explanation:
29 5x+8+x+4=90
6x=78
x=13
30 3x-7+11x-1=90
14x=98
x=7
31 3x+x+8=180
4x=172
x=43
32 6x-1+5x-17=180
11x=198
x=18
Step-by-step explanation: