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2 years ago

Which statement is true about the part of the electromagnetic spectrum that human eyes can detect?

Physics

2 answers:

LUCKY_DIMON [66]2 years ago

7 0

Your answer is B. The human eye can only detect color and Tv waves

Mama L [17]2 years ago

4 0

Answer:

The answer is D i took the quiz and I am in K12 hope it helps!

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A mountain climber weighs 42.0 N. If he climbs a hill 100m high. Calculate the work done in joules

quester [9]

Answer:

The answer is 4200 J.

Explanation:

The formula of work done is, W = F×D where F is the force of an object and D is the distance. Then you just substitute the values into the equation :

W = F×D

F = 42N

D = 100m

W = 42 × 100

= 4200 J

5 0

2 years ago

The cable holding a 2125 kg elevator has a maximum strength of 21,750 N. What is the maximum upward acceleration the cable can g

vivado [14]

Answer:

10.23m/s^2

Explanation:

GIven data

mass of elevator = 2125 kg

Force= 21,750 N

Required

The maximum acceleration upward

F= ma

a= F/m

a=21,750/2125

a= 10.23m/s^2

Hence the acceleration is 10.23m/s^2

4 0

2 years ago

A train moves from rest to a speed of 25 m/s in 30.0 seconds. What is the acceleration?

fredd [130]

Answer:

$a = 0.83\ m/s^2$

Explanation:

<u>Uniform Acceleration </u>

When an object changes its velocity at the same rate, the acceleration is constant.

The relation between the initial and final speeds is:

$v_f=v_o+a.t$

Where:

vf = Final speed

vo = Initial speed

a = Constant acceleration

t = Elapsed time

It's known a train moves from rest (vo=0) to a speed of vf=25 m/s in t=30 seconds. It's required to calculate the acceleration.

Solving for a:

$\displaystyle a=\frac{v_f-v_o}{t}$

Substituting:

$\displaystyle a=\frac{25-0}{30}$

$\boxed{a = 0.83\ m/s^2}$

4 0

2 years ago

A 1000 kg racecar, which is capable of a top speed of 125 m/s, is sitting in a

k0ka [10]

Sitting = no movement
KE=0

5 0

2 years ago

A coil is wrapped with 332 turns of wire on the perimeter of a circular frame (of radius 30 cm). Each turn has the same area, eq

almond37 [142]

Answer:

$E=84.5V$

Explanation:

From the question we are told that:

Number of Turns $N=332turns$

Radius $r= 30cm$

Field Change $B=56mt-29mt=27mt$

Time $t=63ms$

Generally the equation for Magnetic Field is mathematically given by

$\frac{dB}{dt}=\frac{27*10^{-3}}{29*10^{-3}}$

$\frac{dB}{dt}=0.9T/s$

Generally the Flux at 332 turns is mathematically given by

$\phi=N*A*B$

Generally the equation for Area of coil is mathematically given by

$A=\pi*r^2$

$A=\pi*(r*10^{-2})^2$

Since

$\phi=332*\pi*(\theta*10^{-2})^2*B$

Therefore

$\frac{d \phi}{dt}=332*\pi*(900*10^{-4}*\frac{dB}{dt}$

Generally the equation for emf Magnitude is mathematically given by

$E=\frac{d\phi}{dt}$

$E=332*\pi*(900*10^{-4}*0.9$

$E=84.5V$

4 0

2 years ago