All categories

2 years ago

If x3 = 125, what is the value of x? 3 5 12 42

Mathematics

2 answers:

dexar [7]2 years ago

7 0

42

(125/3 = 41.6..., 41.6... rounded is 42)

avanturin [10]2 years ago

4 0

Answer:

Option B.

Step-by-step explanation:

In this question the given expression is x³ = 125 and we have to find the value of x.

x³ = 125

x³ = 5³

x = ∛5³

x = $(5^{3})^{\frac{1}{3} }$

x = $5^{\frac{3}{3}}$

x = 5

Therefore x = 5, Option B is the correct answer.

You might be interested in

Solve for h. -18+7h>12+9h

Evgen [1.6K]

Answer:

$h$

Step-by-step explanation:

$-18+7h>12+9h$

Add 18 to both sides:

$-18+7h+18>12+9h+18$

$7h>9h+30$

Subtract 9h from both sides:

$7h>9h+30$

$-2h>30$

Multiply both sides by -1 and flip the symbol:

$\left(-2h\right)\left(-1\right)$

$2h$

Divide both sides by 2:

$\frac{2h}{2}$

$h$

4 0

2 years ago

The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:

deff fn [24]

Step-by-step explanation:

Given equation of circle is,

${x}^{2} + {y}^{2} - 6y - 12 = 0 \\ by \: compairing \: it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f= - 6 \\ or \: f= - 3 \\ c = - 12$

again the another form of circle is,

${x}^{2} + {(y - k)}^{2} = 21 \\ or \: {x}^{2} + {y}^{2} - 2ky + {k}^{2} - 21 = 0 \\ by \: compairing \:it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\ g = 0 \\f = - k \\ c = {k}^{2} - 21$