Write the equation in Slope-Intercept Form given these two points: (0,8) (-2,2)

Mathematics

1 answer:

In-s [12.5K]2 years ago

8 0

Answer:

y = 3x + 8

Step-by-step explanation:

to find slope intercept if we have 2 points use this formula:

find the slope first: m= (y2-y1)/ (x2-x1)

after get the slope, use this formula:

y-y1 = m(x-x1)

Answer:

m= (y2-y1)/ (x2-x1)

= (2-8)/ (-2-0)= -6/-2 = 3

y-y1 = m(x-x1)

y-8 = 3 (x-0)

y = 3x + 8

hope it helps

You might be interested in

Solve the equation on the interval [0, 27r). 4(sin x)2 - 2 = 0

Ket [755]

$4[sin(x)]^2 - 2 = 0\implies 4[sin(x)]^2=2\implies [sin(x)]^2=\cfrac{2}{4}\implies [sin(x)]^2=\cfrac{1}{2} \\\\\\ sin(x)=\pm\sqrt{\cfrac{1}{2}}\implies sin^{-1}[sin(x)]=sin^{-1}\left( \pm\sqrt{\cfrac{1}{2}} \right)\implies x=sin^{-1}\left( \pm\sqrt{\cfrac{1}{2}} \right)$

$x=sin^{-1}\left( \pm\cfrac{\sqrt{1}}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{1}{\sqrt{2}} \right)\implies x=sin^{-1}\left( \pm\cfrac{\sqrt{2}}{2} \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill x=\cfrac{\pi }{4}~~,~~\cfrac{3\pi }{4}~~,~~\cfrac{5\pi }{4}~~,~~\cfrac{7\pi }{4}~\hfill$

Check the picture below.

4 0

1 year ago

The function f(x) = x] is graphed over the interval [-6, 3]. Which translation of the graph has the domain (-3, 6]? 0 A. g(x) =

bezimeni [28]

An interval graph in graphical theory is indeed an undirected graph formed by an interval set just on true line, with a top for every interval as well as an edge between vertex v to intersections. Graph intervals and these graphs are chordal graphs and graphs that are perfect, and the further discussion can be defined as follows:

Given:

$\bold{function\ f(x) = |x|}$