This is a division problem involving fractions.
57 / (3/4)
57 * (4/3) =
128/3 = 76 pieces of wire
Answer:
<em>The probability that the second ball is red is 71%</em>
Step-by-step explanation:
<u>Probabilities</u>
We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).
The first ball can be red (R) or green (G). The probability that it's red is computed by
The probability is's green is computed by
If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is
If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is
The total probability of the second ball being red is
The probability that the second ball is red is 71%
91, 168 are the answers I believe because 91 can't be made except by multiplying itself by one and 168 can be divided evenly by twelve
In first 40 hours he earns = 7.30 x 40 = $292
Each hour after his rate = 7.20 x 1.5 = $10.80 per hour
In extra four hours he earns = 10.80 x 4 = $43.20
Total earnings = $292 + $43.20 = $335.20
Therefore you don't agree
Hoped this helped you