Answer:
A)
C)
E)
Step-by-step explanation:
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Answer:
t = (D/C - 1) (100/r)
Step-by-step explanation:
D = C(1+rt/100)
D/C = 1 + rt/100
D/C - 1 = rt/100
D/C - 1 = t (r/100)
Therfore,
<h2>t = (D/C - 1) / r/100</h2>
Therefore the last option is correct.
<h2><em><u>
PLEASE MARK MY ANSWER AS BRAINLIEST!!!!!</u></em></h2>
Answer:
(-4+2*2)+8
Step-by-step explanation:
2*2=4
-4+4= 0
0+8= -8
Answer:
y= -1/3x+9.2
Step-by-step explanation:
I believe that it is 9.2 although it could be another number in the 9's.
The slope is (rise) -1 and (run) 3 and the line crosses the y-intercept at what it looks like 9.2
