Solve the problem: -4/9 -8/9

Mathematics

1 answer:

Trava [24]2 years ago

7 0

Answer:

$\frac{-4}{3}$

Step-by-step explanation:

When subtracting fractions with the same denominator (bottom number[s]) you can treat the numerators (top number[s]) like subtraction with whole numbers.

$-4-8$ is equal to -12. Therefore, $\frac{-4}{9} - \frac{8}{9}$ will equal $\frac{-12}{9}$ . But we're not there yet - this fraction can be simplified. We need to find the GCF, or greatest common factor, of -12 and 9. This would be another number that can be divided evenly into these two numbers. The first possible GCF that comes to mind is 3. Let's test that out:

$-12/3 = -4$

$9/3 = 3$

It works! Now we can use this information to simplify the fraction. We replace -12 with -4 and replace 9 with 3. This gives us our final answer, $\frac{-4}{3}$ .

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Solve the following initial-value problem, showing all work, including a clear general solution as well as the particular soluti

Vikki [24]

Answer:

General Solution is $y=x^{3}+cx^{2}$ and the particular solution is $y=x^{3}-\frac{1}{2}x^{2}$

Step-by-step explanation:

$x\frac{\mathrm{dy} }{\mathrm{d} x}=x^{3}+3y\\\\Rearranging \\\\x\frac{\mathrm{dy} }{\mathrm{d} x}-3y=x^{3}\\\\\frac{\mathrm{d} y}{\mathrm{d} x}-\frac{3y}{x}=x^{2}$

This is a linear diffrential equation of type

$\frac{\mathrm{d} y}{\mathrm{d} x}+p(x)y=q(x)$ ..................(i)

here $p(x)=\frac{-2}{x}$

$q(x)=x^{2}$

The solution of equation i is given by

$y\times e^{\int p(x)dx}=\int e^{\int p(x)dx}\times q(x)dx$

we have $e^{\int p(x)dx}=e^{\int \frac{-2}{x}dx}\\\\e^{\int \frac{-2}{x}dx}=e^{-2ln(x)}\\\\=e^{ln(x^{-2})}\\\\=\frac{1}{x^{2} } \\\\\because e^{ln(f(x))}=f(x)]\\\\Thus\\\\e^{\int p(x)dx}=\frac{1}{x^{2}}$