D. 100 kilometers cuz the more kilometers the better the altitude!!!
Answer:
The skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.
Explanation:
To solve the problem it is necessary to go back to the theory of conservation of momentum, specifically in relation to the collision of bodies. In this case both have different addresses, consideration that will be understood later.
By definition it is known that the conservation of the moment is given by:
Our values are given by,
As the skater 1 run in x direction, there is not component in Y direction. Then,
Skate 1:
Skate 2:
Then, if we applying the formula in X direction:
m_1v_{x1}+m_2v_{x2}=(m_1+m_2)v_{fx}
75*5.45-75*1.41=(75+75)v_{fx}
Re-arrange and solving for v_{fx}
v_{fx}=\frac{4.04}{2}
v_{fx}=2.02m/s
Now applying the formula in Y direction:
Therefore the skater 1 and skater 2 have a final speed of 2.02m/s and 2.63m/s respectively.
Answer: If the object is at equilibrium, then the net force acting upon the object should be 0 Newton. Thus, if all the forces are added together as vectors, then the resultant force (the vector sum) should be 0 Newton.
Magnitude: 3.4 N
Direction: 161 deg
HOPE THIS HELPS
Ummm i am not going to be able say i am high
Explanation:
It is given that,
Mas of the car,
Initial speed of the car,
Mass of the truck,
Initial speed of the car,
Final speed of the car,
(a) It is a case of elastic collision. Let is the final velocity of the truck right after the collision. Using the conservation of linear momentum to find it :
(b) Initial kinetic energy is given by :
Final kinetic energy is given by :
The change in mechanical energy of the car truck system in the collision:
The loss in kinetic energy is 10029.39 Joules.
(c) The change in mechanical energy gets changed energy gets changed in the form of heat and light.
Hence, this is the required solution.