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2 years ago

For circle O, m CD=125 and m

Mathematics

2 answers:

omeli [17]2 years ago

7 0

Answer:

<ABO and <BCO equal to 35

Step-by-step explanation:

Measure of arc AD = 180-measure of arc CD= 180-125 =55

m<AOB= 55 ( measure of central angle is equal to intercepted arc)

<OAB= 90 degrees (Tangent makes an angle of 90 degrees with the radius)

In triangle AOB ,

< AB0 = 180-(90+55)= 35 degrees( angle sum property of triangle)

In triange BOC ,< BOC=125 ,

m<, BCO=35 degrees

dybincka [34]2 years ago

3 0

Answer:

In the figure, ABO and BCO equal to 35

Step-by-step explanation:

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f the principal is $350 and the interest rate is 3 percent, what is the simple interest earned in one year?

damaskus [11]

Answer:

$10.50

Step-by-step explanation:

The formula is Balance= Principle (starting amount) x Time x Interest rate. 350 x .03 x 1 is $10.50.

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2 years ago

How do you write equation for rise ove run

SashulF [63]

Y = mx + b

M= your slope or rise over run

B = your y-intercept

For example if the rise was 5 and the run is 6, the equation would say
y = 5/6 + b
The / being your fraction bar

The y-intercept is where your line crosses the y-axis
So say that the line crosses the y-axis at 10
y = 5/6 + 10

That about sums it all up!

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2 years ago

Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear

AlladinOne [14]

Answer:

$x=\frac{83}{50}$

Step-by-step explanation:

we know that

If the three points are collinear

then

$m_A_B=m_A_C$

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

step 1

Find the slope AB

we have

$A(1,\frac{2}{3}),B(x,-\frac{4}{5})$

substitute in the formula

$m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}$

$m_A_B=\frac{\frac{-12-10}{15}}{x-1}$

$m_A_B=-\frac{22}{15(x-1)}$

step 2

Find the slope AC

we have

$A(1,\frac{2}{3}),C(-\frac{1}{2},4)$

substitute in the formula

$m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}$

$m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}$

$m_A_C=-\frac{20}{9}$

step 3

Equate the slopes

$m_A_B=m_A_C$

$-\frac{22}{15(x-1)}=-\frac{20}{9}$

solve for x

$15(x-1)20=22(9)$

$300x-300=198$

$300x=198+300$

$300x=498$

$x=\frac{498}{300}$

simplify

$x=\frac{83}{50}$

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3 years ago

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kakasveta [241]

20 feet high. I hope this helps!

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podryga [215]

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2 years ago