Hey there!
I'll assume we're using the slope-intercept form equation:
y = mx + b
m = slope
b = y-intercept
First, we keep the y, because it's value depends on the x value given.
Next, we find the slope. Slope is defined as rise/run, so we take two points on the graph, find how much taller one is from another, and how far right/left they are, put those values over each other, and we have out slope (m).
Finally, we need to determine the y-intercept, and that's as simple as seeing where the line crosses the y axis and writing down that value.
Hope this helps!
Answer:
a) distance covered by hare d1 = 8t
b) distance covered by tortoise d2 = 5t + 550
c) ∆d = 550 - 3t
Step-by-step explanation:
Given;
Speed of hare u = 8m/s
Speed of tortoise v = 5 m/s
Initial distance of tortoise d0 = 550 m
a) using the equation of motion;
distance covered = speed × time + initial distance
d = vt + d0
For hare;
d0 = 0
Substituting the values;
d1 = 8t + 0
d1 = 8t
b)using the equation of motion;
distance covered = speed × time + initial distance
d2 = vt + d0
For tortoise;
d0 = 550m
Substituting the values;
d2 = 5t + 550
d2 = 5t + 550 m
c) the number of meters the tortoise is ahead of the hare.
∆d = distance covered by tortoise - distance covered by hare
∆d = d2 - d1
Substituting the values;
∆d = (5t + 550) - 8t
∆d = 550 - 3t
To find the pre image you need to back track on the image. To get to the image you used (x-6,y+8). Now you need to use the exact opposite to get back to the pre image. For this you would change the signs to look like (x+6,y-8). Now we just apply this to (-4,1).
(-4+6,1-8)
(2,-7) should be the pre image point.
This question doesn’t make sense, double check you wrote it right
I have no idea at all man I’m so sorry your math sucks