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2 years ago

Rita bought a pair of jeans for 89 the sales tax rate is 11 percent what is total amount she paid for jeans

Mathematics

2 answers:

Vsevolod [243]2 years ago

8 0

The price of jeans = $89

The sales tax rate = 11%

So first we have to find 11% of $89.

11% of 89 = 89 × (11/100) = (89×11)/100 = 979/100 = 9.79

We have got the sales tax amount = $9.79

So price of jeans = $89 and sales tax = $9.79

The total amount Rita paid for jeans = $(89+9.79) = $98.79

So we have got the required answer.

The total amount Rita paid for jeans = $98.79.

vivado [14]2 years ago

6 0

Answer

Step-by-step explanation:

this is the final step

price = 89

sales tax =9.97

you take your price then add the sales tax with it

total = 98.79

see its vary simple its just a matter of finding the total of your sales tax and adding it to the original price . hopes this simplified version help have a good day =)

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Sharon paid $78 sales tax on a new camera. If the sales tax is 6.5%, what was the cost of the camera?

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Answer:

$1200

Step-by-step explanation:

$1200

Step-by-step explanation:

78 = 6.5%

This means that if you divide 78 by 6.5, you get the equivalent of 1% of the price:

78 ÷ 6.5 = 12

So 1% = 12

Now simply multiply this by 100 to get the full answer:

12 x 100 = 1200

So the camera cost $1200!

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Sveta_85 [38]

Using the binomial distribution, the probabilities are given as follows:

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

The values of the parameters for this problem are:

n = 10, p = 0.4.

The probability that more than 4 weigh more than 20 pounds is:

$P(X > 4) = 1 - P(X \leq 4)$

In which:

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0061$

$P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403$

$P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209$

$P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150$

$P(X = 4) = C_{10,4}.(0.4)^{4}.(0.6)^{6} = 0.2502$

Hence:

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0061 + 0.0403 + 0.1209 + 0.2150 + 0.2502 = 0.6325$

$P(X > 4) = 1 - P(X \leq 4) = 1 - 0.6325 = 0.3675$

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

The probability that fewer than 3 weigh more than 20 pounds is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

For more than 7, the probability is:

$P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.4)^{8}.(0.6)^{2} = 0.0106$

$P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016$

$P(X = 10) = C_{10,10}.(0.4)^{10}.(0.6)^{0} = 0.0001$

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

More can be learned about the binomial distribution at brainly.com/question/24863377

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Question ok iterations help would be greatly appreciated!

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2 years ago

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svetoff [14.1K]

Nicoles pattern:

1
5
17
53
161

Ian’s pattern:

0
1
3
7
15

Ordered pair:

(1, 0)
(5, 1)
(17, 3)
(53, 7)
(161, 15)

Table 1 -

Sequence 1:

9
11
13
15
17

Sequence 2:

5
8
11
14
17

Ordered pair:

(9, 5)
(11, 8)
(13, 11)
(15, 14)
(17, 17)

Table 2 -

Sequence 1:

20
16
12
8
4

Sequence 2:

20
17
14
11
8

Ordered pair:

(20, 20)
(16, 17)
(12, 14)
(8, 11)
(4, 8)

Table 3 -

Sequence 1:

1
3
7
15
31

Sequence 2:

40
24
16
12
10

Ordered pair:

(1, 40)
(3, 24)
(7, 16)
(15, 12)
(31, 10)

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1 year ago