What is the difference between constructing a regular hexagon and constructing an equilateral triangle?

Mathematics

2 answers:

Leto [7]2 years ago

6 0

Answer:

A.For the hexagon construction, every arc along the circle is connected, but for the equilateral triangle construction, every other arc

along the circle is connected.

Step-by-step explanation:

tresset_1 [31]2 years ago

4 0

Answer:

Its not b since thats what i just got wrong on the test so your down to 3 options

Step-by-step explanation:

wadsdawdawf

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I need a little extra help with number three

diamong [38]

Answer:

The answer to your question is:

Step-by-step explanation:

Data

f(x) = -2x² + 8x - 2

Process

-2x² + 8x = y + 2

-2(x² - 4x + 4) = y + 2 - 8

-2(x - 2)² = y - 6

(x - 2)² = 1/2 (y - 6)

Vertex = (2, 6)

Axis of symmetry = x = 2

y-intercept

f(0) = -2(0)² + 8(0) - 2

f(0) = 0 + 0 - 2

f(0) = -2

Domain (-∞, ∞)

Range (-∞, 6]

See the graph below

6 0

2 years ago

Simplified (4x3 - 5x2 + 3x) + (-2x3 - x2 + 6x)

bogdanovich [222]

Answer:

Answer is imaginary roots

Step-by-step explanation:

$({4x}^{3} - {5x}^{2} + 3x) + ( - {2x}^{3} - {x}^{2} + 6x) \\ 2 {x}^{3} - 6 {x}^{2} + 9x = 0 \\ dividing \: by \: x \\ 2 {x}^{2} - 6x + 9 = 0 \\ dividin g\: by \: 2 \\ {x}^{2} - 3x + \frac{9}{2} = 0 \\ shifting \: the \: constant \: term \: on \: right \: side \\ {x}^{2} - 3x = - \frac{9}{2} \\ adding \: \frac{1}{2} \times (coefficient \: of \: x) \: whole \: square \\$