They don't need gas because satellites rotate around the world using our planet's gravitational force as centripetal force. That as well as since there is no air in space, it doesn't have to work against air resistance. This way it doesn't lose energy by going around and around the Earth.
Hope this helps, have a BLESSED day! :-)
If it takes 42 minutes to load 3 1/2 trucks, then it takes 42 / 3.5 = 12 minutes to load a single truck. Multiplying the number of minutes per truck by 6.5 yields the time it will take to load. In this case 12 x 6.5 = 78 minutes would be required to load 6 1/2 trucks. The formula for the time taken is t = 12n, where t is the time in minutes and n is the number of trucks.
The term b^2 / 4a^2 is not added to the left side of the equation, because the term that was added to the right was not either b^2 / 4 a^2.
As you can see the ther b^2 / 4a^2 that appears in the last step of the table is inside a parenthesis, which is preceded by factor a.
Then, you need to apply the distributive property to know the term that you are really adding to the right side, i.e. you need to mulitply b^2 / 4a^2 * a which is b^2 / 4a.
That means that you are really adding b^2 / 4a to the right, so that is the same that you have to add to the left, which is what the last step of the table shows.
That situation is reflected by the statement "<span>The
distributive property needs to be applied to determine the value to add
to the left side of the equation to balance the sides of the equation".</span> That is the answer.
The distance traveled by the arrow and horizontal velocity are directly proportional, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.
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Time of motion of the projectile</h3>
If the horizontal distance the projectile would travel before hitting the target is 70.67 m, the time of motion of the projectile is calculated as;
X = Vx(t)
t = X/Vx
t = X/Vcosθ
t = (70.67) / (45 x cos10)
t = 1.6 s
When the archery target is moved further away from the archer, the archer needs increase the initial velocity of the arrow assuming the angle of projection is constant.
Since the distance and horizontal velocity are directly proportional to each other, thus when the distance increases, an increase in initial velocity will allow the arrow to hit the target.
Learn more about velocity of projectile here: brainly.com/question/12870645