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2 years ago

Giving stars and thanks :) also be ready for more if you can help me !

Mathematics

2 answers:

Ber [7]2 years ago

8 0

Number 1 is B and number 2 I belive is C. I hope I'm rightt, and I hope this helps.

SCORPION-xisa [38]2 years ago

6 0

X-intercept: Put y = 0 in the equation y = 2x - 6 and solve for x. y-intercept: Put x = 0 in the equation y = 2x - 6 and solve for x.

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Someone pls help me I will make you Brainly

emmasim [6.3K]

Answer:

C) f(x)=2(25)x

For question 4: f(x)=4()^x

Step-by-step explanation: The correct answer from the choices listed above is option C. IT would be f(x) = 2(25)x that is an equivalent function to f(x) = 2(5)^2x. You can square directly 5 since it will still follow the rules for exponents.

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2 years ago

1.) What is the domain of a function y = x + 3 when the range is {7, 4,3}

mart [117]

Answer:

Step-by-step explanation:

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2 years ago

Find an equation for the nth term of the arithmetic sequence. -3, -5, -7, -9, ...

tankabanditka [31]

Answer:

a(n) = -3 - 2(n-1)

Step-by-step explanation:

The most general formula for the nth term of an arithmetic sequence (such as this sequence is) is

a(n) = a(1) + c(n-1), where c is the common difference.

Here a(1) = -3 and c = -2.

Thus,

a(n) = -3 - 2(n-1).

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2 years ago

EXPERTS/ACE/GENIUSES/TRUSTED HELPERS HELPP ME

Bad White [126]

Answer is B, the graph increases by about 0.28 per year

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2 years ago

Plz..... Solve this questions for me...

faust18 [17]

$6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================$

$7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================$

$8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10$

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2 years ago