Answer:
t= 137.5 s
Explanation:
So if we are wanting to figure out how long it takes runner B to catch runner A. we must first set the slope of each runner equal to one another
<u>Slopes:</u>
Runner A: y = 7.50x + 55
Runner B: y = 7.90 x
sooooo
7.50 x + 55 = 7.90 x
- 7.50 x - 7.50 x
55 = .40 x
55/.40 = .40 x / .40
x = 137.5 s
t= 137.5 s
7.50 * 137.5 + 55 =1086.25 m
7.90 * 137.5 = 1086.25 m
Answer:the first one was x
the second one is y
Explanation:
Answer:
1.19 m/s²
Explanation:
The frequency of the wave generated in the string in the first experiment is f = n/2l√T/μ were T = tension in string = mg were m = 1.30 kg weight = 1300 g , μ = mass per unit length of string = 1.01 g/m. l = length of string to pulley = l₀/2 were l₀ = lent of string. Since f is the second harmonic, n = 2, so
f = 2/2(l₀/2)√mg/μ = 2(√mg/μ)/l₀ (1)
Also, for the second experiment, the period of the wave in the string is T = 2π√l₀/g. From (1) l₀ = 2(√mg/μ)/f and from (2) l₀ = T²g/4π²
Equating (1) and (2) we ave
2(√mg/μ)/f = T²g/4π²
Making g subject of the formula
g = 2π√(2√(m/μ)/f)/T
The period T = 316 s/100 = 3.16 s
Substituting the other values into , we have
g = 2π√(2√(1300 g/1.01 g/m)/200 Hz)/3.16
g = 2π√(2 × 35.877/200 Hz)/3.16
g = 2π√(71.753/200 Hz)/3.16
g = 2π√(0.358)/3.16
g = 2π × 0.599/3.16
g = 1.19 m/s²