I am going to explain this using the substitution method, considering it appears to be the best in this situation.
We know (from the bottom equation) that y can equal 3x+20. Using this knowledge, we substitute the y in the top equation for 3x+20. Now, we have an equation that looks like this:
3x+20=x^2+2x
Now we need to move x to one side and then do some radicals (square roots).
Subtract the 2x on the right (since it is smaller, negatives = NONONO), which will give you
x+20=x^2
Now, we take the square root of both sides to get
rad(x+20)=x
Now we have to simplify. 20 doesn't have a square root, but 4 goes into 20, and 4 has a square root of 2. This now becomes
2rad(x+5)
This doesn't simplify any further... we have a problem... no way to isolate x as far as my knowledge goes... Sorry, can't help you any further than that, but another person or your teacher might be able to. R.I.P...
Old enough for Matt to seek vengeance against her
Studio = 7 yards by 4 yards
Area = 7*4 = 28 square yards.
Area of square carpet = 1 yard * 1 yard = 1 square yard
Number needed = Area of studio / Area of square carpet = 28 / 1 = 28
Number needed = 28
Answer:
Step-by-step explanation:
Find the equation of the segment going from (0,-5) to (3,7)
y intercept = -5
Slope = (-5 - 7) / (0 - 3) = -12/-3 = 4
equation: y = 4x - 5
g(x) = x^2 / f(x)
f(x)= (4x - 5)
g(x) = x^2 / (4x - 5)
g'(x) = x^2 * (4x - 5)^-1
g'(x) = 2x*(4x - 5)^-1 + (-1) *4* x^2 (4x - 5)^-2
I will leave that monster the way it is and just find g'(1)
g'(1) = 2(1) * (4(1) - 5)^-1 + (-1) (1)^2 *4* (4(1) - 5)^-2
g'(1) = 2(1) * (-1)^-1 + (-1) (1)^2 *4 * (-1)^2
g'(1) = -2 + (-1) (1)^2 (4)
g'(1) = - 2 + (-1) (1)^2 (4)
g'(1) = - 2 - 4
g'(1) = - 6
