Centripetal acceleration is (speed-squared) / (radius)
CA = (6 m/s)² / (9 m)
CA = (36 m²/s²) / (9 m)
CA = (36/9) (m²/m·s²)
<em>Centripetal acceleration = 4 m/s²</em>
Answer:
29.96m/s
Explanation:
Given parameters:
Initial speed = 25.5m/s
Acceleration = 1.94m/s²
Time = 2.3s
Unknown:
Final speed of the car = ?
Solution:
To solve this problem, we are going to apply the right motion equation:
v = u + at
v is the final speed
u is the initial speed
a is the acceleration
t is the time taken
Now insert the parameters and solve;
v = 25.5 + (1.94 x 2.3) = 29.96m/s
given that snow is projected at an angle of 40 degree
It range is given as a = 19 ft
now we can use the formula of horizontal range
<u>so its initial speed must be 7.6 m/s</u>
Answer:
S = 2 π R
R (mean) = 92.9E6 miles
S = 2 * 3.14 * 92.9E6 miles = 5.84E8 miles
Answer:
first one i think is this. work = 1/2 kx^2 = 1/2 Fx
2nd, is 0.08 J
Explanation:
EE = ½ kx²
EE = ½ (400 N/m) (0.02 m) ²
EE = 0.08.
THIRD, Velocity of the stone is 4 m/s when it leaves catapult.