Answer:
the period T of whole motion should be twice the value for half at he bottom so T is 0.2sec.
w is angular frequency
formula:2π/T
now k is spring constant
F/R-->mw²
putting values:70*(2π/0.2)²
=4.9x10⁶
so we can say that SHM is not affected by the amplitude of the bounce.
Answer: Option 2
Explanation:
Option 1 is wrong because there are 2 protons and 2 neutrons in nucleus.
Option 3 is wrong because there are two electrons moving around nucleus.
Option 4 is wrong because electrons are negatively charged and are moving around the nucleus.
Option 5 is wrong because there equal amount of protons and electrons with 2 each.
Answer:
Option D is the correct answer.
Explanation:
Since value of angular acceleration is constant, the body has only centripetal acceleration.
Centripetal acceleration
We have radius = 7.112 cm = 0.07112 m
Frequency, f = 1975 rpm = 32.92 rps
Angular frequency, ω = 2πf = 2 x π x 32.92 = 206.82 rad/s
Substituting in centripetal acceleration equation,
Option D is the correct answer.