We have that
<span>4x -2y =22------> clear variable y
2y=4x-22--------> y=4x/2-22/2---------> y=2x-11-----> equation 1
2x + 4y = 6------> equation 2
substitute equation 1 in equation 2
2x+4*[2x-11]=6-----> 2x+8x-44=6----> 10x=50------> x=5
then
y=2x-11----> y=2*5-11----> y=-1
</span>
Tbe question doesn't state the number of days he walked to school out of 20 school days in the
Month of February.
Answer:
Kindly check explanation
Step-by-step explanation:
To. Obtain the fractional representayion for the number of days he walked to school ;
Let the number of days he walked to school = 10 (this is an hypothesized value)
Number of school days in February = 20
Fraction = 10 /20 = 0.5
The percentage of times walked to school : multiply the fraction obtained above by 100%
0.5 * 100% = 50%
Just put the desired value and proceed uSing the steps described above.
Step-by-step explanation:
Revin imediat...... ✨.
9.625 in decimals hope this helps
Answer:
<em>55mph
. None of the options are correct
</em>
Step-by-step explanation:
If the speed varies inversely as the time it takes to drive, then v ∝ 1/t. where;
v is the speed
t is the time taken
Hence;
v = k/t with k being the constant of proportionality.
Since it takes Kris 5 hours when driving at 55 mph, we will substitute v = 55mph and t = 5 hours. into the equation above to get the value of k as shown:
55 = k/5
Cross multiply
k = 55*5
k = 275
Hence, to calculate the speed it will Martin to drive for 5 hours, we will substitute k = 275 and t = 5 into the original equation v = k/t as shownl
v = 275/5
v = 55 mph
<em>Hence, we can conclude that Martin will also need to drive at a speed of 55mph if he wants to take 5hours.</em>