He __________ uses a series of gears to adjust the output speed of the engine.
1 answer:
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The car will halt at a minimum distance of 98.57 meters on a rainy day having a friction coefficient of 0.109.
Calculation of the minimum distance-
Provided that :
- the speed of the car = 52 km/h
= 52 x 0.278 m/s = 14.45 m/s
- Friction coefficient, μ = 0.109
the regular force exerted on the car,
Along X-direction, the force is
Friction acts in the opposite way along the x-axis
⇒-μ
⇒-μmg =
⇒ μg
Utilizing the motion equation-
v² = u²+ 2 .a. s
The final speed, v=0 m/s
⇒0² = (14.45)² - 2 μg .s
⇒2 * 0.109 *9.8 *s = (14.45)² = 208.8
⇒s = 208.8 / 2.14 = 97.57 m
It is concluded that the car will halt at a minimum distance of 98.57 meters.
Learn more about friction coefficient here:
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Answer:
Explanation:
Kinetic energy can be found using the following formula.
where <em>m</em> is the mass and <em>v</em> is the velocity.
The mass of the toy plane is 20 kilograms and the velocity is 10 meters per second.
Substitute the values into the formula.
Solve the exponent first.
- (10 m/s)²= 10 m/s *10 m/s= 100 m²/s²
Multiply the last two numbers together.
Multiply by 1/2 or divide by 2.
- 1 kilogram square meter per square second is equal to 1 Joule.
- Our answer of 1000 kg*m²/s² is equal to 1000 Joules
The kinetic energy of the toy plane is <u>1000 Joules</u>