Ask question

Ask question

All categories

2 years ago

16

Mr. Lopez wrote the equation 32g+8g-10g=150 on the board. Four students explained how to solve for g. Alyssa: “I added 32 and 8

to get 40, subtracted 10 to get 30, and then subtracted 30 from 150 to find the value of g, which is 120.” Rahul: “I added 32, 8, and 10 to get 50, and then I subtracted 150 to find the value of g, which is –100.” Toni: “I subtracted 18 from 32 to get 14, which I then divided into 150 to find the value of g, which is ” Wilhem: “I added 32 and 8 to get 40, subtracted 10 to get 30, and then divided both sides by 30 to find the value of g, which is 5.” Which student’s work is correct?

2 answers:

Vaselesa [24]2 years ago

7 0

Answer:

Wilhem

Step-by-step explanation:

The given equation is

$32g+8g-10g=150$

Step 1 : Add 32g and 8g.

$(32g+8g)-10g=150$

$(32+8)g-10g=150$

$40g-10g=150$

Step 2: Subtract 10 from 40.

$(40-10)g=150$

$30g=150$

Step 3: Divide both sides by 30, find the value of g.

$\frac{30g}{30}=\frac{150}{30}$

$g=5$

The value of g is 5.

Therefore, Wilhem is correct.

natta225 [31]2 years ago

7 0

Answer:

whilem

Step-by-step explanation:

use your math skillz dumb dumb. Read the question and don't be imtimadated by it.

You might be interested in

3y + x = 12<br> What is the value of x when y = 3?

Andre45 [30]

Step-by-step explanation:

3y + x = 12

When y = 3, we have 3(3) + x = 12.

=> 9 + x = 12, x = 3.

6 0

2 years ago

Pyramid A is a square pyramid with a base side length of 12 inches and a height of 8 inches. Pyramid B is a square pyramid with

yan [13]

Answer:

<em>The volume of pyramid B is 64 times the volume of pyramid A.</em>

<em></em>

Step-by-step explanation:

Given:

Two square pyramids A and B.

Side Length of A, $s_A =$ 12 inches

Height of A, $h_A =$ 8 inches

Side Length of B, $s_B =$ 48 inches

Height of B, $h_B =$ 32 inches

To find:

How many times bigger is the volume of pyramid B than pyramid A?

OR

$V_B$ is how many times bigger than $V_A$ ?

Solution:

First of all, let us have a look at the formula for volume of a pyramid:

$V=\dfrac{1}{3} \times \text{Area of Base} \times \text{Height}$

Here, base is square, so:

$V=\dfrac{1}{3} \times s^2 \times h$

Volume of pyramid A:

$V_A=\dfrac{1}{3} \times s_A^2 \times h_A$

$\Rightarrow V_A=\dfrac{1}{3} \times 12^2 \times 8 = 384\ inch^3$

Volume of pyramid B:

$V_B=\dfrac{1}{3} \times s_B^2 \times h_B$

$\Rightarrow V_B=\dfrac{1}{3} \times 48^2 \times 32 \\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 4^2 \times 4\\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 64\\\Rightarrow V_B= 24576\ inch^3 = 384\times 64\ inch^3\\\Rightarrow V_B = V_A\times 64\ inch^3$

<em>The volume of pyramid B is 64 times the volume of pyramid A.</em>

3 0

2 years ago

If 1 inch = 2.5 centimeters, how many centimeters are there in 40 inches

alekssr [168]

100 centimeters . Because 40 × 2.5 = 100

6 0

2 years ago

Determine the zeros of the function f(x) = 3x^2 -7x+1

IceJOKER [234]

I will use the quadratic formula.

$\text{The zeros of function:}\ f(x)=0\\\\f(x)=3x^2-7\\\\f(x)=0\to3x^2-7x+1=0\\\\a=3;\ b=-7;\ c=1\\\\b^2-4ac=(-7)^2-4\cdot3\cdot1=49-12=37\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-(-7)-\sqrt{37}}{2\cdot3}=\dfrac{7-\sqrt{37}}{6}\\\\x_2=\dfrac{-(-7)+\sqrt{37}}{2\cdot3}=\dfrac{7+\sqrt{37}}{6}$

6 0

2 years ago

The half-life of a particular element is 10 days. If you begin with 40 grams of the element write an exponential decay function

galben [10]

Answer:2.25 grams

Step-by-step explanation:

To find the remaining mass of an element, apply the following:

m0 = m/(2^n), where m0 is the remaining mass, m as the original mass and n as the number of half lives that have passed.

we have m, we just have to find n. To find n,

24/6 = 4 half lives have passed.

Applying the first formula,

m0 = (36)/(2^4) = 36/8 = 2.25 grams

Hope this helps, brainliest would be appreciated :)

4 0

1 year ago