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2 years ago

If fx= 6x-4 what is when x=8

Mathematics

2 answers:

umka2103 [35]2 years ago

7 0

on putting the value of x in the given function, we get :-

$f(8) = 6 \times 8 - 4$

$f(8) = 48 - 4$

$f(8) = 44$

ra1l [238]2 years ago

6 0

Answer:

Step-by-step explanation:

fx=6(8)-4

fx=48-4

fx=44

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Hey! Last day for me to do Algebra before exams so this is an emergency!! Help would definitely be appreciated and do NOT answer

il63 [147K]

Part 1 -

1. f(x) = 5(x-2)^2 + 4

axis of symmetry: x = 2

vertex: (2, 4)

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axis of symmetry: x = -6

vertex: (-6, -5)

3. f(x) = 2x^2 + 8x - 7

axis of symmetry: x = -2

vertex: (-2, -15)

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2 years ago

PLEASE ANSWER THIS 30 POINTS BRAINLIEST WILL BE GIVEN PICTURE INCLUDED!!

den301095 [7]

The first step is to quickly factor each of the five equations... to do so, find the right factors of the 3rd given number so that they add up in an equal number to the second number... 14 = -7 • -2 and -9 = -7 + -2

a^2 - 9a + 14 = 0
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{2,7}

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(a + 7) (a + 2)

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{-2, -7}

a^2 + 3a - 10 = 0
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5 0

2 years ago

Read 2 more answers

In the figure, is an exterior angle to triangle .

ludmilkaskok [199]

Answer:

I don't have c but I do have a and b

Step-by-step explanation:

Part A)

Angle 3 is 103° because 77° + ∠3= 180° and ∠3 = 180° - 77° = 103°

Part B)

Angle 4 is 77° because ∠3 + ∠4 = 180° and ∠4 = 180° - 103° = 77°

These are the answers for k12

3 0

2 years ago

What is the value of y?<br> log^464 = y<br> OA. 16<br> OB. 8<br> OC. 3<br> OD. 4

Paraphin [41]

The value of y in the given logarithmic equation is 3. The correct option is C. 3

<h3>Evaluating Logarithmic equation </h3>

From the question, we are to determine the value of y in the given logarithmic equation

The given equation is

$log_{4}64=y$

By applying one of the laws of logarithm, we get

$64 = 4^{y}$

Now, express 64 in index form,

$4^{3} = 4^{y}$

Since the bases are equal, we can equal the powers to get

3 = y

∴ y = 3

Hence, the value of y in the given logarithmic equation is 3. The correct option is C. 3

Learn more on Logarithmic equations here: brainly.com/question/237323

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1 year ago

Find the value of the variable y, where the sum of the fraction 2/y-3 and 6/y+3 is equal to the quotient.

NISA [10]

Answer:

Here we need to solve:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} }$

The sum of the fractions is equal to the quotient between the fractions.

Notice that the two values:

y = 3

y = -3

make the denominator equal to zero, so those values are restricted.

We can simplify the right side to get:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} } = \frac{2*(y + 3)}{6*(y - 3)} = 3*\frac{y + 3}{y - 3}$

Now we can multiply both sides by (y - 3)

$(y - 3)*(\frac{2}{y - 3} + \frac{6}{y + 3 }) = 3*(y + 3)\\2 + 6*\frac{y -3}{y + 3} = 3*(y + 3)$

Now we can multiply both sides by (y + 3)

$(2 + 6*\frac{y -3}{y + 3})*(y + 3) = 3*(y + 3)*(y + 3)$

$2*(y + 3) + 6*(y - 3) = 3*(y + 3)*(y + 3)\\\\2*y + 6 + 6*y - 18 = 3*(y^2 + 2*y*3 + 9)\\\\8*y - 12 = 3*y^2 + 6*y + 33\\\\0 = 3*y^2 + 6*y + 33 - 8*y + 12\\\\0 = 3*y^2 - 2*y + 45$

First, let's see the determinant of that quadratic equation:

$D = (-2)^2 - 4*3*45 = -536$

We can see that it is negative, thus, there are no real solutions of the equation.

Thus, there is no value of y such that the origina equation is true,

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2 years ago