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2 years ago

Describe the way electromagnets

Physics

1 answer:

Leona [35]2 years ago

3 0

Answer:

Assuming you mean how they work,

Explanation:

Electromagnets work by wrapping the wire around an iron core and attaching it to an electric charge.

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A person sitting still in a moving airplane is considered to be... (SP1a) a. Motionless in relation to everything in the plane.

vichka [17]

Answer:

C. Both a and b

Explanation:

Firstly, persons and objects in a moving plane as described in this question, are moving at the same speed as the plane even if there is no individual movement of these objects.

However, this question describes a person sitting still in a moving plane. This means that;

- The person is motionless in relation to everything in the plane i.e the person is not moving even if other things in the plane are.

- The person is in motion compared to everything on the ground i.e. the person is moving at the same speed as the plane, hence, in comparison with the ground, the person is moving.

Therefore, options A and B are correct

6 0

2 years ago

The diagram shows a stone suspended under the surface of a liquid from a string. The stone experiences a pressure caused by the

Ivan

Where is the diagram? What is the question?

6 0

2 years ago

How much force should a mother exert to lift a 5.0-kg child

andrew11 [14]

Answer:

F = 49N

Explanation:

F = mg

F = 5kg × 9.8m/s^2

F = 49kg.m/s^2 = 49N

8 0

2 years ago

Behavior that is harmful to one's self is? 10 pts

Sophie [7]

The answer is distressing

8 0

3 years ago

Read 2 more answers

The 1.53-kg uniform slender bar rotates freely about a horizontal axis through O. The system is released from rest when it is in

OlgaM077 [116]

Answer:

The spring constant = 104.82 N/m

The angular velocity of the bar when θ = 32° is 1.70 rad/s

Explanation:

From the diagram attached below; we use the conservation of energy to determine the spring constant by using to formula:

$T_1+V_1=T_2+V_2$

$0+0 = \frac{1}{2} k \delta^2 - \frac{mg (a+b) sin \ \theta }{2} \\ \\ k \delta^2 = mg (a+b) sin \ \theta \\ \\ k = \frac{mg(a+b) sin \ \theta }{\delta^2}$

Also;

$\delta = \sqrt{h^2 +a^2 +2ah sin \ \theta} - \sqrt{h^2 +a^2}$

Thus;

$k = \frac{mg(a+b) sin \ \theta }{( \sqrt{h^2 +a^2 +2ah sin \ \theta} - \sqrt{h^2 +a^2})^2}$

where;

$\delta$ = deflection in the spring

k = spring constant

b = remaining length in the rod

m = mass of the slender bar

g = acceleration due to gravity

$k = \frac{(1.53*9.8)(0.6+0.2) sin \ 64 }{( \sqrt{0.6^2 +0.6^2 +2*0.6*0.6 sin \ 64} - \sqrt{0.6^2 +0.6^2})^2}$

$k = 104.82\ \ N/m$

Thus; the spring constant = 104.82 N/m

The angular velocity can be calculated by also using the conservation of energy;

$T_1+V_1 = T_3 +V_3 \\ \\ 0+0 = \frac{1}{2}I_o \omega_3^2+\frac{1}{2}k \delta^2 - \frac{mg(a+b)sin \theta }{2} \\ \\ \frac{1}{2} \frac{m(a+b)^2}{3} \omega_3^2 + \frac{1}{2} k \delta^2 - \frac{mg(a+b)sin \ \theta }{2} =0$