Answer:
1 2/6 3 3/4
Step-by-step explanation:
A.) For the Junior Varsity Team, mean would be the appropriate measure of center since the data is <span>symmetric or well-proportioned while we should use standard deviation for getting the measure of spread since it also measures the center and how far the values are from the mean.
b.) For the Varsity Team, the median would be the appropriate measure of the center since the data is skewed left and not evenly distributed so median could be used since it does not account for outliers while we use IQR or interquartile range in measuring the spread of data since IQR does not account for the data that is skewed. </span>
The exponential parent function is D
Correct answer is C.
m + 3s = 50
the total number of questions is 20. since the paper is made of only multiple choice and short answer questions, the sum of the multiple choice and short answer questions should be 20.
since multiple choice is 'm' and short answer is 's'
then m + s = 20
but theres no option for that
if we take the number of points
points for 1 multiple choice question - 1
then points for m number of multiple choice questions = 1 * m = m
points for 1 short answer - 3
then points for s number of short answer question = 3 * s = 3s
then total number of points = m + 3s
and the total number of points = 50
therefore
m + 3s = 50
this is the correct answer C.
Answer:
1,705 elk
Step-by-step explanation:
7,750 / 50 = 155 groups of elk
155 groups x 11 per group = 1,705 elk.