Answer:
80pi-60pi
Step-by-step explanation:
To find how much Juan ran, we must find the circumference.
pi *30*2=60*pi (which is how much Juan ran.)
pi*40*2=80*pi (which is how much Miguel ran)
80pi-60pi would be how much farther Miguel ran than Juan.
Answer:
116
Step-by-step explanation:
290% as a decimal is 2.9. "Of" means multiply. You can now multiply 2.9 by 40 to get the answer 116.
Given the expression,
We will have to rationalize the denominator first. To rationalize the denominator we have to multiply the numerator and denominator both by the square root part of the denominator.
![[(8x-56x^2)(\sqrt{14x-2})]/[(\sqrt{14x-2})(\sqrt{14x-2})]](https://tex.z-dn.net/?f=%20%5B%288x-56x%5E2%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%5B%28%5Csqrt%7B14x-2%7D%29%28%5Csqrt%7B14x-2%7D%29%5D%20)
If we have 
, we will get 
by multiplying them. And 
.
So here in the problem, we will get,
![[(8x-56x^2)(\sqrt{14x-2})]/(14x-2)](https://tex.z-dn.net/?f=%20%5B%288x-56x%5E2%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%2814x-2%29%20)
Now in the numerator we have 
. We can check 8x is common there. we will take out -8x from it, we will get,
And in the denominator we have 
. We can check 2 is common there. If we take out 2 from it we will get,
So we can write the expression as
![[(-8x)(7x-1)(\sqrt{14x-2})]/[2(7x-1)]](https://tex.z-dn.net/?f=%20%5B%28-8x%29%287x-1%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%5B2%287x-1%29%5D%20)
is common to the numerator and denominator both, if we cancel it we will get,
We can divide -8 by the denominator, as -8 os divisible by 2. By dividing them we will get,
So we have got the required answer here.
The correct option is the last one.
Answer:
une entreprise a dépensé en tout 14 400e en 2001 pour l'entretien de ses voitures a. recopier et compléter le tableau ci-dessous. b. calculer la dépense moyenne pour l'entretien d'une voiture. c. les dépense d'entretien ont été représentées dans le diagramme circulaire ci-contre, mais la légende a été effacée. rétablir cette légende.
Step-by-step explanation:
He is wrong because as long as they have the same terms/ variables behind the number it doesn’t matter about if it is positive or negative
