Answer:
do you have any vocabulary to help you with this or no
This is because iodine is nonpolar. You also saw that the iodine was less soluble inethanol and acetone than it was in carbon tetrachloride. Ethanoland acetone are more polar thancarbon tetrachloride. Iodine was more soluble in them than it was in water because they are less polar than water.
Answer:
The charge on H is partial positive and the charge on I is partial negative.
δ+H−Iδ−
The percent ionic character is 5.15 %.
Explanation:
The ionic compound is formed by the complete transfer of electron from one atom to another. The one atom thus carry the positive charge while the other which accept the electron became negative. like in case of NaCl .This have 100% ionic character.
In covalent bond, the bond is formed by the sharing of electron between two atoms. The one atom which greatly pull the electrons towards itself is became partial negative while the other became partial positive atom. In this way electronegativity difference is created. For example in HI bond hydrogen is partial positive and have 2.2 electronegativity while the electronegativity of iodine is 2.66.
Percent ionic character:
Formula:
%ionic character = [1- e∧-(0.25)(x)²] × 100
X= XA - XB
XA = higher electronegativity
XB = lower electronegativity
X = 2.66 - 2.2
X = 0.46
now we will determine the %ionic character.
%ionic character = [1- e∧-(0.25)(x)²] × 100
%ionic character = [1- e∧-(0.25)(0.46)²] × 100
%ionic character = [1- e∧-(0.25)(0.2116)] × 100
%ionic character = [1- e∧-(0.0529)] × 100
%ionic character = [1- 0.9485)] × 100
%ionic character = 0.0515 × 100
%ionic character = 5.15%