Answer:
Step-by-step explanation:
Group Before After
Mean 80.27 78.27
SD 12.76 12.92
SEM 3.85 3.89
N 11 11
df = 10
standard error of difference = 0.798
The mean of Before minus After equals 2.00
Given a=0.01, |t(0.005, df=10)|=3.17 (check student t table)
So 99% CI is
2±t*s
--> 2±3.17*0.798
--> -0.5 < µd< 4.5
Answer:-0.5 < µd< 4.5
Answer is -7
Plug 4 in for g(x) and solve to get x=-7.Plug x=-7 in for f(x).
Answer:
9/20
Step-by-step explanation:
45/100.
5 is a common factor so simplified = 9/20