Answer:
a. Following an injury that breaks the surface of the skin. blood vessels dilate as a result of histamine release from mast cells and other damaged cells.
b. The blood forms a clot and upon drying, a scab forms a barriers between the body and the environment, while phagocytes work to clear the underlying debris from the wound site.
c. Blood vessels begin to re-grow into the wound while fibroblasts begin process of replacing the blood clot with Collagen
d. The remodeling phase then occurs as fibrosis and regeneration of tissues may continue for prolonged period of time.
Explanation:
Hello. Although you did not have all the answer options for the blanks presented in the sentences above, it is possible to conclude that the words in bold are the most appropriate to fill these spaces.
That's because when we cut ourselves, the blood vessels on the surface of our skin rapidly dilate, allowing a flow of blood to be observed. This dilation is accomplished by the release of histamine, which is released by mast cells, which are glands that regulate the immune response. At this point, it is important that any impuzera or microorganism, close to the wound site, is removed and this site undergoes cleaning. This is done by phagocytes, which are intended to prevent the cut from becoming the entrance to a bacterial infection.
Then the blood vessels begin to move and grow again across the wound, with the aim of covering this opening. In this comment, fibroblasts begin to apply collagen and replace the blood clot formed to prevent blood loss. Collagen will be responsible for maintaining the skin and tissues that will be rebuilt in the remodeling phase.
Explanation:
option D is the correct answer ..
hope this will be helpful to you .
plz mark my answer as brainlist if you find it useful
Answer:
The correct answer would be 10.
The cell cycle can be divided into four phases namely gap 1 (G₁) phase , synthesis (S) phase, gap 2 (G₂) phase, and mitosis (M) phase.
DNA (deoxyribonuceic acid) content is only replicated and doubled in the S phase. However, the chromosome number remains the same. It can be explained as the number of chromosomes remains the same (2n) but number of chromatids doubles (4n) after S phase.
The number of chromatids restores to 2n in daughter cells after completion of mitosis.
Hence, if number of chromatids in metaphase was 20 i.e. 4n then the number of chromosomes (2n) would be 10.
Hence, 10 chromosomes or 5 pairs of chromosome would be present in the cell during its G₁ phase.
Answer:
The answer is A.
Explanation:
To test if the selenium from the mine has an effect on the fish living in the lake which i assume is close to the mine, testing the tissue of the fish from that lake and comparing it to the selenium levels of the fish from a nearby lake would be a testable hypothesis because there is a comparable aspect and there should be a difference in the numbers between the fish from the two lakes because of their distance to the mine.
I hope this answer helps.
