Answer:
0.5 A
Explanation:
N = 20, A = 50 cm^2 = 50 x 10^-4 m^2, dB = 6 - 2 = 4 T, dt = 2 s, R = 0.4 ohm
The induced emf is given by
e = - N dФ/dt
Where, dФ/dt is the rate of change of magnetic flux.
Ф = B A
dФ/dt = A dB/dt
so,
e = 20 x 50 x 10^-4 x 4 / 2 = 0.2 V
negative sign shows the direction of magnetic field.
induced current, i = induced emf / resistance = 0.2 / 0.4 = 0.5 A
After impact velocity = 14.968 ft/s
Weight and mass of Bullet and wooden block:
Bullet: w = 1oz = 1/16 lb m = 0.001941 lb
wooden block : W = 5lb M = 0.15528 lb
velocity of block and bullet immediately after impact:
Σmv1 + ΣImp = mv2
Resolving vertical component
( m× v₀cos30⁰) + 0 = ( m+M) v'
v' = ( m× v₀cos30⁰)/ (m+M)
v' = 14.968 ft/s
Horizontal and vertical component of the impulse exerted by block on the bullet:
Here we will apply the principle of impulse and momentum.
Horizontal component:
-mv₀ cos30⁰ + RxΔt =0
RxΔt = mv₀sin30⁰
= 0.001941 × 1400sin30⁰
RxΔt = 1.3587 lb.s
Vertical component:
-mv₀cos30⁰ + RyΔt = -mv'
RyΔt = m( v₀cos30⁰-v')
RyΔt = 0.001941(1400cos30⁰ - 14.968)
= 2.32 lb.s
Learn more about impact here:
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Answer:
61.0168 g/mol Explanation:
Answer:
23.3 g/cm3
Explanation:
First of all, this should be in the math section. I just so happen to also be good at math. Cheers!
Answer:
The correct answer is t = 0.92s
Explanation:
Initial velocity v0 = 3.0 m/s
Displacement Δy = ?
Acceleration a = -9.8m/s2
Final velocity v = -6.0m/s
Time t=? Target unknown
We can use the kinematic formula missing Δy to solve for the target unknown t:
V=v0+at
We can rearrange the equation to solve to t:
V-v0=at
t= v-v0/a
Substituting the known value into the kinematic formula gives:
t= (-6.0m/s)-(3.0m/s)
————————————
-9.8m/s2
= -9m/s
—————-
-9.8m/s2
=0.92s