Which is a greater y-intercept (0,-1) or (0,-2)

Mathematics

1 answer:

kolezko [41]2 years ago

3 0

Answer:

(0,-1)

Step-by-step explanation:

-1 is less than -2 so -1 have a greater value since it is closer to the origin (0,0)

You might be interested in

A student expressed the sum of 2 whole numbers as 5 times (8+3).What are the 2 whole numbers?

Marta_Voda [28]

Well if the two numbers are equal to 5x(8+3).

Lets say that these two numbers are X and Y,

So that would be X + Y = 5(8+3)

which means X + Y = 55

You could write that as a fuctions Y = 55 - X

Now by using the graph you get and the X values of [0,55] ( This means every value from 0 to 55 ), you will get a X and Y value that if you added up together will give you the value of 8(5+33)

An examples for the answers would be

(0,55) (1,54) (2,53) (3,52) (4,51) (5,50) (6,49) ... it goes on until x reaches 55.

8 0

2 years ago

two buses leave towns 604 mi apart at the same time and travel toward eachother. One bus travels 9 mi/h faster than the other on

muminat

Answer:

s = 71 mph, and s+9 = f = 80 mph

Step-by-step explanation:

The distances the two busses travel add up to 604 mi.

Letting f be the faster speed and s the slower. Then f = s + 9 (mph).

Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi. Solve this for s:

4s + 36 + 4s = 604 mi, or 8s = 568. Finally, s = 71 mph, and s+9 = f = 80 mph.

3 0

2 years ago

A right square pyramid with base edges of length $8\sqrt{2}$ units each and slant edges of length 10 units each is cut by a plan

seropon [69]

Answer:

32 $unit^{3}$

Step-by-step explanation:

Given:

The slant length 10 units
A right square pyramid with base edges of length 8 $\sqrt{2}$

Now we use Pythagoras to get the slant height in the middle of each triangle:

$\sqrt{10^{2 - (4\sqrt{2} ^{2} }) }$ = $\sqrt{100 - 32}$ = $\sqrt{68}$ units

One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.

$\sqrt{68-(4\sqrt{2} ^{2} )}$ = $\sqrt{68 - 32}$ = 6 units.

Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid: