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2 years ago

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A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a

force of 3.4 N. What is the mass of the ice? Assume the force of friction is not significant.

1 answer:

laiz [17]2 years ago

8 0

Answer:

Mass, m = 0.49 kg

Explanation:

It is given that,

A block of ice is sliding down a ramp of slope 45° to the horizontal. At the bottom of the ramp, the block strikes a wall with a force of 3.4 N.

We need to find the mass of the ice.

On a sloping surface, the force with which it strikes is given by :

$F=mg\cos\theta\\\\m=\dfrac{F}{g\cos\theta}\\\\m=\dfrac{3.4}{9.8\times \cos(45)}\\\\m=0.49\ kg$

So, the mass of the ice block is 0.49 kg.

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The graph above shows the position x as a function of time for the center of mass of a system of particles of total mass 6. 0 kg

kumpel [21]

The resulting change in momentum of the system will be +18.6 Ns. The momentum is conserved.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

m is the mass =6.0 kg

t is the time interval=2 second

From Newton's second law;

$\rm \triangle P =m \triangle V \\\\ \triangle P= m(\frac{\triangle x}{\triangle t} )\\\\$

From the graph;

$\rm \triangle t = 2sec\\\\ \triangle x = (12-8) m$

The change in the momentum is;

$\rm \triangle P = m\tr(\frac{v-u}{t}) \\\\ \triangle P =9.3 \times \frac{12-8}{2} \\\\ \triangle P= +18.6 \ N.s$

Hence, the resulting change in momentum of the system will be +18.6 Ns.

To learn more about the law of conservation of momentum, refer;

brainly.com/question/1113396

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1 year ago

bagirrra123 [75]

That's <em>false</em>. It's just the opposite. As you become more fit, your heart becomes able to accomplish more with each beat, so your resting heart rate DEcreases.

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2 years ago

A particle starts from the origin at t = 0 with an initial velocity of 4.8 m/s along the positive x axis.If the acceleration is

tia_tia [17]

Answer:

Part a)

Velocity = 6.9 m/s

Part b)

Position = (3.6 m, 5.175 m)

Explanation:

Initial position of the particle is ORIGIN

also it initial speed is along +X direction given as

$v_x = 4.8 m/s$

now the acceleration is given as

$\vec a = -3.2 \hat i + 4.6 \hat j$

when particle reaches to its maximum x coordinate then its velocity in x direction will become zero

so we will have

$v_f = v_i + at$

$0 = 4.8 - 3.2 t$

$t = 1.5 s$

Part a)

the velocity of the particle at this moment in Y direction is given as

$v_f_y = v_i + at$

$v_f_y = 0 + 4.6(1.5)$

$v_f_y = 6.9 m/s$

Part b)

X coordinate of the particle at this time

$x = v_x t + \frac{1}{2}a_x t^2$

$x = 4.8(1.5) - \frac{1}{2}(3.2)(1.5^2)$

$x = 3.6 m$

Y coordinate of the particle at this time

$y = v_y t + \frac{1}{2}a_y t^2$

$y = 0(1.5) + \frac{1}{2}(4.6)(1.5^2)$

$y = +5.175 m$

so position is given as (3.6 m, 5.175 m)

5 0

2 years ago

What affect would using a 12V car battery have on the operation of your circuit? (Do not try this.) What would happen to the cur

k0ka [10]

Answer:

Incomplete question

This is the completed question

If the resistor in the circuit had a larger resistance then the current would be then have to be proportionally smaller. Because the batteries each give off 1.5 volts then the current would have to be the variable that would change. What affect would using a 12V car battery have on the operation of your circuit? (Do not try this.) What would happen to the current? What would happen to the resistor?

Explanation:

Using ohms law as our basis

Ohms law state that, the voltage in an ohmic conductor is directly proportional to the current

V∝I

Resistance is the constant of proportionality

Then

V=iR

Since we want a relationship between current and resistance.

then, I=V/R

So, current is inversely proportional to Resistance

as the current increase the resistance reduce and as the current reduces the resistance increases.

a. So, increasing the voltage from 1.5V to 12V increases the current In the circuit because voltage Is directly proportional to I.

From ohms law

V=iR

When v =1.5V

I=1.5/R

When V increase to 12V

I=12/R

I.e, it increases by a factor of 8. Eight times it's initial value

b. Now, the resistance in the circuit is the constant of proportionality and it doesn't change in a given circuit expect when using a variable resistoa r like rheostat.

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2 years ago

PHYSICS, HELP PLZ??!! 100PTS

romanna [79]

Hi there!

We can begin by calculating the time the ball takes to reach the highest point of its trajectory, which can be found using the following:

$t_{max} = \frac{vsin\theta}{g}$

Where:

tmax = (? sec)

vsinθ = vertical comp. of velocity = 10sin(48) = 7.43 m/s)

g = acceleration due to gravity (9.8 m/s²)

We can solve for this time:

$t_{max} = \frac{7.43}{9.8} = 0.758 s$

When the ball is at the TOP of its trajectory, its VERTICAL velocity is equivalent to 0 m/s. Thus, we can consider this a free-fall situation.

We must begin by solving for the maximum height reached by the ball using the equation:

$d = y_0 + v_{0y}t + \frac{1}{2}at^2$

d = displacement (m)

vi = initial velocity (7.43 m/s)

a = acceleration due to gravity

d = displacement (m)

y0 = initial VERTICAL displacement (28m)

Plug in the values:

$d = 28 + 7.43(0.758) + \frac{1}{2}(-9.8)(0.758^2) = 30.817 m$

Now, we can use the rearranged kinematic equation:

$t = \sqrt{\frac{2h}{g}}$

$t = \sqrt{\frac{2(30.817)}{9.8}} = 2.51 s$

Add the two times together:

$0.758 + 2.51 = \boxed{3.266 s}$

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1 year ago