Answer:
x = π/3, x = 5π/3, x = 4π/3
Step-by-step explanation:
Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3 = 0.
Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.
Similarly:
The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.
So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.
It depend on what question an algebric can have as many but depends???
Answer:
D. -x2 + 2x -3
Step-by-step explanation:
the first step is we open all the brackets then it will be :
x2 - 3x - 2x2 + 5x - 3
= x2 - 2x2 - 3x + 5x - 3
= -x2 + 2x -3
Answer:
3^4
Step-by-step explanation:
Simplifying an expression with expression with exponents:
If they are dividing, we keep the base and subtract the exponents. For example:
In this question:
That is correct since the line in T is not straight it would eventually hit the third quadrant
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