potassium chromate - k2cro4. ,,silver nitrate-agno3. ,, potassium nitrate-kno3 ,,Silver chromate- ag2cro4
Answer:
B. N2
Explanation:
The triple bonds pull the atoms closer together, and since N2 is the only molecule with the triple bond, it is the shortest bond length.
The half-reaction are:
Cd ---> Cd(OH)₂
The oxidation number of Cd changed from 0 to +2. So, the number of mol electron transferred here is 2.
NiO(OH) --> Ni(OH)₂
The oxidation number of Cd changed from +3 to +2. So, the number of mol electron transferred here is 1.
Now, the greatest common factor would be 2. So, we use n=2 for the formula for ΔG°. F is Faraday's constant equal to 96,485 J/mol e.
ΔG° = nFE° = (2)(96,485)(1.5) =<em> 289,455 J</em>
Answer:
The answer to your question is below
Explanation:
a) HCl 0.01 M
pH = -log [0.01]
pH = - (-2)
pH = 2
b) HCl = 0.001 M
pH = -log[0.001]
pH = -(-3)
pH = 3
c) HCl = 0.00001 M
pH = -log[0.00001]
pH = - (-5)
pH = 5
d) Distilled water
pH = 7.0
e) NaOH = 0.00001 M
pOH = -log [0.00001]
pOH = -(-5)
pH = 14 - 5
pH = 9
f) NaOH = 0.001 M
pOH =- log [0.001]
pOH = 3
pH = 14 - 3
pH = 11
g) NaOH = 0.1 M
pOH = -log[0.1]
pOH = 1
pH = 14 - 1
pH = 13
For the answer to the questions above,
a) Ag2CO3(s) => Ag2O(s)+CO2(g)
<span>b) Cl2(g)+2(KI)(aq) => I2(s)+2(KCl)(aq) (coefficients are for balanced equation) </span>
<span>net ionic is Cl2(g)+2I- => I2(s)+2Cl-(aq) </span>
<span>c) I2(s)+3(Cl2)(g)=>2(ICl3)
</span>I hope I helped you with your problem