DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Answer:
y+9=3/4(x-8)
Step-by-step explanation:
y-y1=m(x-x1)
y-(-9)=3/4(x-8)
y+9=3/4(x-8)
Answer:
90
Step-by-step explanation:
circumference of total circle = 16 pi
16 pi / 4 pi = 4
1 / 4 =25%
1/4 * 360 = 90
