Slope-intercept form: y = mx + b
(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)
For lines to be parallel, they have to have the same slope.
y = 6x + 6 The slope of this line is 6, so the parallel line's slope is also 6.
Now that you know m = 6, substitute/plug it into the equation:
y = mx + b Plug in 6 for "m" in the equation
y = 6x + b To find "b", plug in the point (20, 1) into the equation
1 = 6(20) + b
1 = 120 + b Subtract 120 on both sides to get "b" by itself
1 - 120 = 120 - 120 + b
-119 = b Now that you know b = -119, plug it into the equation
y = 6x - 119
I believe that a flat surface continuing in all directions is called a plane.
The angle congruent to ∠6 are ∠8, ∠3, ∠9 and ∠14
<h3>How to find congruent angles?</h3>
When parallel lines are cut by a transversal, angle relationships are formed. They include corresponding , alternate and many more.
L║m
n ║ q
Therefore, the angles congruent to ∠6 by alternate or corresponding relationship are as follows:
∠6≅∠8≅∠3≅∠9≅∠14
learn more on angles here: brainly.com/question/15443897
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