Check if there is a giggle throughout the full equation, since there isn’t, we group the equation and we get
(4ax-10bx)+(6ay-15by)
Factor out the gcf of the two groups
2x(2a-5b)+3y(2a-5b)
Not sure how to explain this step in words but so do this
(2x+3y)(2a-5b)
The solution is (2x+3y)(2a-5b)
Answer:
x = - 2
y = 6
Step-by-step explanation:
The best way to do this is to put - 3x in for y in the second equation.
4x - 2(-3x) = - 20 Watch the signs. You have 2 minus signs.
4x - - 6x = -20 Change - - 6x to 6x
4x + 6x = - 20 Add
10x = - 20 Divide by 10
x = -20/10
x = - 2
============================
Find y
y = - 3x
y = -3 * -2
y = 6
Answer:
Step-by-step explanation:
<u>1- digit numbers: </u>
- 1 to 9, number of digits = 9
<u>2- digit numbers:</u>
- 10 to 99, number of digits = 2(99 - 9) = 180
<u>3- digit numbers:</u>
- 100 to 999, number of digits = 3(999 - 99) = 2700
This is more than we have, but we know the number of pages is 3-digit.
<u>Let it be x, then we have:</u>
- 9 + 180 + 3(x - 99) = 1074
- 3(x - 99) = 1074 - 189
- 3(x - 99) = 885
- x - 99 = 885/3
- x - 99 = 295
- x = 295 + 99
- x = 394
The correct answer is C) (5m^50 - 11n^8) (5m^50 + 11n^8)
We can tell this because of the rule regarding factoring the difference of two perfect squares. When we have two squares being multiplied, we can use the following rule.
a^2 - b^2 = (a - b)(a + b)
In this case, or first term is 25m^100. So we can solve that by setting it equal to a^2.
a^2 = 25m^100 -----> take the square root of both sides
a = 5m^50
Then we can do the same for the b term.
b^2 = 121n^16 ----->take the square root of both sides
b = 11n^8
Now we can use both in the equation already given
(a - b)(a + b)
(5m^50 - 11n^16)(5m^50 + 11n^16)
She should move it one place to the left because there is one zero in ten so however many zeros there are in the multiple of 10 that's how many times you move it. Then, you move it left to divide and right to multiply. Hope I helped!