What voltage battery would you need to send 2.5A of current through a light bulb of resistance 3.6 ohm
1 answer:
<h3><u>Given</u> :</h3>
Current flow light bulb = 2.5
Resistance of light bulb = 3.6Ω
<h3><u>To Find </u>:</h3>We have to find voltage of battery
➠ As per ohm's law, current flow through a conductor is directly proportional to the applied potential difference.
➝ V ∝ I
➝ <u>V = I × R</u>
Where, R is the resistance of conductor.
⇒ V = I × R
⇒ V = 2.5 × 3.6
⇒ <u>V = 9 volt</u>
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Answer:A
Explanation:
In R-L circuit current is given by
where i=current at any time t
R=resistance
L=Inductance
at t=0 approaches to 1
therefore
i=0
when t approaches to ,
approaches to zero
thus
thus we can say that initially circuit act as broken wire with zero current
and it increases exponentially with time and act as ordinary connecting wire