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2 years ago

Name three non-collinear points. Please help :)

Mathematics

1 answer:

Elena L [17]2 years ago

8 0

Answer: M, K, N

Step-by-step explanation: In order points to be non-collinear,

the points can't lie on the same line.

So what we are looking for are points that don't lie on the same line.

The correct answer would be points M, K, N.

Although M, K, R, and R, N, K, look like points that are non-collinear,

they aren't all points since R is the name of the plane.

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2 years ago

In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.

Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

$\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}$

In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, $B$ . Then, we can find the third side. Using the law of sines, we can find:

$\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}$

We can use this to solve for $B$ :

$13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}$

$B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1$

Now, we can find $C$ :

$C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}$

Using this, we can find $c$ :

$\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}$

$c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}$

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2 years ago

Can some one help me find x?

Gnom [1K]

Answer:

x = 20

Step-by-step explanation:

Exterior angles are equal.

7x - 3 = 6x + 17

Add 3 and subtract 6x to both sides.

x = 20 is the answer.

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2 years ago

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Aleksandr-060686 [28]

Answer:

V = 6079.04 ft³

Step-by-step explanation:

The volume (V) of a cylinder is calculated as

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V = 3.14 × 11² × 16

= 3.14 × 121 × 16

≈ 6079.04 ft³ ( to the nearest hundredth )

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1 year ago