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pickupchik [31]

2 years ago

6

a lead block drops its temperature by 5.90 degrees celsius when 427 J of heat are removed from it. what is the mass of the block

?(unit=kg) IM GIVING 30 POINTS FOR THE CORRECT ANSWER

1 answer:

Airida [17]2 years ago

7 0

Answer:

577g

Explanation:

Given parameters:

Temperature change = 5.9°C

Amount of heat lost = 427J

Unknown:

Mass of the block = ?

Solution:

The heat capacity of a body is the amount of heat required to change the temperature of that body by 1°C.

H = m c Ф

H is the heat capacity

m is the mass of the block

c is the specific heat capacity

Ф is the temperature change

Specific heat capacity of lead is 0.126J/g°C

m = H / m Ф

m = $\frac{427}{0.126 x 5.9}$ = 577g

Mass of the lead block is 577g

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irinina [24]

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$M_1=m_av_a$

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Solving for $v_a$

$v_a=\frac{m_av'_a+m_bv'_b}{m_a}$

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$K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2$

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