Answer:
1.32×10²⁵ atoms of sulfate are contained in 22 units of it
Explanation:
1 unit = 1 mol
Al₂(SO₄)₃ → Aluminum sulfate
As 1 unit = 1 mol, 1 unit has 6.02×10²³ atoms of aluminum sulfate.
Let's make a rule of three:
1 unit of Al₂(SO₄)₃ contains 02×10²³ atoms
Then, 22 units of Al₂(SO₄)₃ must contain (22 . 6.02×10²³) / 1 = 1.32×10²⁵ atoms
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Answer:
2.61
Explanation:
pH+pOH=14, so sub in 11.39 for pOH, then subtract it over to get pH=2.61
if you have any questions, leave them in the comments and i will try to answer them, if this helped, pls give brainliest.
<span>H</span>₃<span>PO</span>₄<span> - Phosphoric Acid :
H</span>₃<span>PO</span>₄<span> = 1.0 * 3 + 31.0 + 16.0 * 4 = 98.0 g/mol
hope this helps!</span>
