Let z = sin(x).
.. z^2 -2z = 2
.. z^2 -2z +1 = 3
.. (z -1)² = 3
.. z -1 = ±√3
.. z = 1 -√3 . . . . . the positive solution is extraneous
sin(x) = 1 -√3
It is true that (x+2)(x+3) = x2 +5x + 6
Y=3/1x+-1 hope this is correct
Answer:
h=(1/3pi r^2)V
Step-by-step explanation: