Find the slope of the line that passes through the points (3,0) and (3,-2).
2 answers:
When given the points (x1,y1) and (x2,y2)
slope=(y2-y1)/(x2-x1)
we have
(3,0) and (3,-2)
(x,y)
x1=3
y1=0
x2=3
y2=-2
slope=(-2-0)/(3-3)=-2/0=undefined since you caon't divide by zero
answer is D
undefined
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Wouldn't you do 18.20 divide that by .65 & get 28. So the tool was used for 28 minutes
X^2-3x = x(x-3)
x^2-9 = x^2 - 3^2 = (x-3)(x+3)
HCF = x-3
Only you can do that yourself, no one online can do that for you.
the answer would be b hope this help