The group of measures which would lead to the provided conclusion is the range is 7, the mean of the data is 12, the median is 12 and the mode is 11.
Given that, the data is around 12. If another measurement were taken, it would probably be around 12.
We need to find which group of measures would lead to this conclusion.
<h3>What are the mean, median and mode of the data set?</h3>
The mean of the data is the average value of the given data. The mean of the data is the ratio of the sum of all the values of data to the total number of values of data.
The median of the data is the middle value of the data set when it arrange in ascending or descending order. The data is around 12 which suggests that the median is 12.
Median=12
The mode of a data set is the value, which occurs most times for that data set. The value which has the highest frequency in the given set of data is known as the mode of that data set.
Mean and mode is around the median. For this case, the mean of the data is 12 and the mode is 11.
Mode=11
Mean=12
Thus, the group of measures which would lead to the provided conclusion is the range is 7, the mean of the data is 12, the median is 12 and the mode is 11.
Learn more about the mean, median and mode here;
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Answer:
9
Step-by-step explanation:
x = first number
3x = second number
2x = third number
27 = x + 3x+ 2x
27 = 6x
x=4.5 (first number)
3(4.5) = 13.5 (second number)
2(4.5) = 9 (third number)
(4.5 + 13.5 + 9) /3 = 9
Wow after doing all that I realized that all you had to do was 27/3 since there's 3 numbers.
Answer:
x=larger no
y= smaller no
Step-by-step explanation:
x+y=7--------(1)
x=16 + 2y------(2)
(2)--->(1)
16+2y+y = 7
3y + 16 = 7
3y = -9
y = -3//
so x=10
B
the probability of an event ( A<span> ), given that another ( </span>B<span> ) has already occurred.
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