Answer:
Burgers: 12
French Fries: 34
Step-by-step explanation:
Answer:
I can't help you, it doesn't indicate what you need
Since the question is incomplete, answer will be subjective. An example of Evaluating Expressions is find h + 8 − 9 j − h; where h = 7 and j = 5.
<h3>What is the Evaluating Expressions?</h3>
The evaluating expressions is known to be a form of digital and printable board work that can help students in working on substituting values in terms of variables of an algebraic expression.
Evaluating the Expression below:
h + 8 − 9 j − h;
Therefore, where h = 7 and j = 5
7+ 8 − 9 (5) − 7.
SO: 7 + 8 - 45 -7
= -37
Therefore the answer to the Evaluating Expression is -37.
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Answer:
Hey buddy whatsup? All good
Coming to the question fig 1 and 3 aren't functions
Coz.... Reason for fig 1... Every distinct element of domain must have a unique element in codomain, but in this fig the same element has more than two unique elements which is a relation not a function.
Reason for fig 3 every element in domain must have an unique element in codomain but in this fig the element c doesn't have any unique element hence it isn't a function.....
Thank you
Answer:
x=a/y
Step-by-step explanation:
