Answer:
Quotient: x+7
Remainder: -2
Step-by-step explanation:
Divide the terms (x² ÷ x =x)↓
(x² + 11x + 26) ÷ (x + 4) =x
Subtract x² + 4x (You have to the sign if each term)
(x² + 11x + 26) ÷ (x + 4) =x
-x² - 4x
-------------------
7x + 26
Divide the terms (7x ÷ x = 7)
x² + 11x + 26) ÷ (x + 4) =x + 7
Multiply the quotient by the dividend (x + 4) × 7 = 7x+28
(x² + 11x + 26) ÷ (x + 4) =x
-x² - 4x
-------------------
7x + 26
7x + 28
------------------
= -2 Remainder
Answer:
8.95feet
Step-by-step explanation:
The set up is a right angled triangle where;
The camera's horizontal distance from the focus point = 26feet = Adjacent;
The height of the camera above the floor = Opposite = x
Angle of elevation = 19°
According to TOA in trig identity;
Tan theta = opp/adj
Tan 19 = x/26
x = 26tan 19
x = 26(0.3443)
X = 8.95feet
Hence the camera is placed at a height of 8.95feet above the floor
