Step 1) Find the area of the trapezoid:
Step 2) Find the answer:
So the answer is
56
B:
i=43 degrees
ii= 2 minutes
C:
10 degrees per minute
Sorry that's all I got
Any real number line ranges from negative infinity to positive infinity. A real number number line consists of all the rational and irrational numbers. Let us take three intervals which contain both the rational and irrational numbers.
First interval: [3,4]
Since every integer is a rational number, 3 and 4 are both rational. In this interval there occurs the value of π (3.14159..) which is an irrational number.
Second interval : [0,2]
0 and 2 are integers and hence are rational. In this interval, occurs √2 (1.41421...) is an irrational number.
Third interval : [2,3]
In this interval, Eulers number 'e' lie whose value is (2.718281.. )
Hence we can conclude that, there occurs an irrational number between any two rational number.
Answer:
9. m(YZ) = 102°
10. m(JKL) = 192°
11. m<GHF = 75°
Step-by-step explanation:
9. First, find the value of x
4x + 3 = 3x + 15 (inscribed angle that are subtended by the same arc are equal based on the inscribed angle theorem)
Collect like terms
4x - 3x = -3 + 15
x = 12
4x + 3 = ½(m(YZ)) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Plug in the value of x
4(12) + 3 = ½(m(YZ))
48 + 3 = ½(m(YZ))
51 = ½(m(YZ))
Multiply both sides by 2
51*2 = m(YZ)
102 = m(YZ)
m(YZ) = 102°
10. First, find the value of x.
7x + 5 + 6x + 6 = 180° (opposite angles in an inscribed quadrilateral are supplementary)
Add like terms
13x + 11 = 180
13x = 180 - 11
13x = 169
x = 169/13
x = 13
7x + 5 = ½(m(JKL)) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Plug in the value of x
7(13) + 5 = ½(m(JKL))
96 = ½(m(JKL))
Multiply both sides by 2
2*96 = m(JKL)
m(JKL) = 192°
11. First, find x.
5x + 15 = ½(11x + 18) (inscribed angle of a circle = ½ the measure of the intercepted arc)
Multiply both sides by 2
2(5x + 15) = 11x + 18
10x + 30 = 11x + 18
Collect like terms
10x - 11x = -30 + 18
-x = -12
Divide both sides by -1
x = 12
m<GHF = 5x + 15
Plug in the value of x
m<GHF = 5(12) + 15
m<GHF = 60 + 15
m<GHF = 75°
Answer:
The graphs of the two function will not intersect.
Step-by-step explanation:
We are given a quadratic function f(x).
Also g(x) is given by a set of values as:
x g(x)
1 -1
2 0
3 1
As g(x) is a linear function hence we find out the equation of g(x) by the slope intercept form of a line: y=mx+c
let g(x)=y
when x=1 , g(x)=-1
-1=m+c----(1)
when x=2 , g(x)=0
0=2m+c------(2)
Hence, on solving (1) and (2) by method of elimination we get:
m=1 and c=-2
Hence, the equation of g(x) is:
g(x)=x-2
So clearly from the graph we could see that the graph of the two functions will never intersect.
